quick math question

[Neotuck]

how do you find the average g/s from vents/geysers/volcanoes?

I know there's an equation using the eruption period and active period I'm just not sure what it is

[Lilalaunekuh]

Let´s say you have a steam vent:

4Kg/s emission

30s / 600s eruption cycle

100 cycle / 200 cycle active period

 

4Kg/s * 30s / 600s * 100cycle / 200cycle = 0,1Kg/s

[Neotuck]

15 minutes ago, Lilalaunekuh said:

4Kg/s * 30s / 600s * 100cycle / 200cycle = 0,1Kg/s

I'm assuming you do the division first before you multiply? 

I have a slush geyser with these stats:

30.2Kg/s

233s / 1035s eruption

39.4 cycle / 73.2 cycle active

Using that equation the average is 3.6kg/s right?

 

[PhailRaptor]

1 minute ago, Neotuck said:

I'm assuming you do the division first before you multiply? 

I have a slush geyser with these stats:

30.2Kg/s

233s / 1035s eruption

39.4 cycle / 73.2 cycle active

Using that equation the average is 3.6kg/s right?

 

Yes, and yes.  Note for gaseous sources, this assumes they never go Overpressure, which depending on their rate can be very easy for them to do.

[Stoof]

9 minutes ago, Neotuck said:

I'm assuming you do the division first before you multiply?

No maths genius here, but does it matter if you multiply or divide first?

[blash365]

3 minutes ago, Stoof said:

No maths genius here, but does it matter if you multiply or divide first?

Not in nested fractions.

[Lilalaunekuh]

2 hours ago, Neotuck said:

I'm assuming you do the division first before you multiply? 

It´s commutative so you can do as you please xD (order doesn´t matter here)

[beowulf2010]

Even though this has effectively been answered, the "best" way of determining average output over the span of the dormancy period is to take the displayed output and multiply it by the eruption percentage and the active/dormant percentage. 

If you just turn the eruption and active numbers to flat uptime percentages, it's a lot easier to keep straight in your head. Or at least it is for me. 

So, in Neotuck's example, we multiply his 30.2kg/s by the 22.5% eruption percent (233/1035) and them multiply in the active/dormant percentage of 53.8% (39.4/73.2).

[Neotuck]

2 hours ago, beowulf2010 said:

Even though this has effectively been answered, the "best" way of determining average output over the span of the dormancy period is to take the displayed output and multiply it by the eruption percentage and the active/dormant percentage. 

If you just turn the eruption and active numbers to flat uptime percentages, it's a lot easier to keep straight in your head. Or at least it is for me. 

So, in Neotuck's example, we multiply his 30.2kg/s by the 22.5% eruption percent (233/1035) and them multiply in the active/dormant percentage of 53.8% (39.4/73.2).

I still get 3.6Kg/s

[avc15]

3 minutes ago, Neotuck said:

I still get 3.6Kg/s

that's because it's exactly the same method, just explained in an easier to understand way

[beowulf2010]

Yep. 3.6657kg/s. You got it right. 

I just find it's easier for me to "remember" the math if I just convert the eruption and active sets into a percentage before modifying the base output. Same result, different formula appearance. 

[PhailRaptor]

The idea is to think of the Eruption and Active periods as % uptime so you can do a fuzzy calculation without needing to really do the math.  It gives you a better at-a-glance perspective when you first discover a particular Geyser/Fumerole/Volcano.  Even before you analyze for Activity Period, you should have a good idea of whether the Geyser in question has any potential or not.  The higher the base rate, and the closer the Eruption Period is to 100%, the better the probability that the Geyser will be useful.

[onebit]

Here's a google sheet to calculate the average.

@beowulf2010 I got 3,659.4.

[beowulf2010]

23 minutes ago, onebit said:

Here's a google sheet to calculate the average.

@beowulf2010 I got 3,659.4.

6.3 grams per second difference. Close enough for my work. Also, remember that Excel uses the entire number in its calculations whereas I'm sure I rounded to the 100th's place at best.