Sour gas

[Carnis]

32 minutes ago, Zarquan said:

OK.  Take 2 on the math. 

Starting with 10 kg sour gas 538.9 C, which results in 6.7 kg natural gas -161.5 C, 5.025 kg polluted water -20 C, 1.675 kg of CO2 -20 C, and 10 kg 70 C crude oil. 

I transfer heat from sour gas to crude oil up to 400 C.  That cools the sour gas from 538.9 to 245 C.

My natgas leave my exchanger with crude at 150C, this should be easily achievable, given the lower SHC of sourgas.

Quote

 

I then transfer heat from sour gas to polluted water.  I cool the sour gas to -0.5 C, which heats the polluted water to 90 C.

 

How do you get another reactant to -0.5C and the other to 90C?? Aquatuners?

Quote

 

That leaves 36.5 C that needs to be removed, resulting in 692,350 J that need to be removed.  We will use thermoregulators to move the heat from the sour gas to the polluted water and CO2, heating each to 110 C.  The polluted water can take 421,800 J.  The CO2 can take 184,200 J of heat.  That covers 606,000 J of heat, therefore only leaving 86,300 to be removed.  That can be dealt with by using 7.2 wheezeworts. 

It will take 21 thermoregulators to manage this heat transfer at the rate of 10 kg/s of sour gas.

21 thermoregulators costs 5040 W to run.  Easily covered by the power gains.

Once we can move the sulfur, we can reduce this cost significantly and the system should net cool.

 

So.. I'd like to see this build with 21 thermoregulators, without breaking hydrogen pipes.

*

I don't disagree, it can be done, but it has to be methane aquatuners or lox aquatuners, 21 thermoregs is too much.

[Zarquan]

15 minutes ago, Carnis said:

How do you get another reactant to -0.5C and the other to 90C?? Aquatuners?

Reverse flow heat transfer.  The coldest sour gas interacts with the coldest polluted water and the hottest sour gas interacts with the hottest polluted water.

15 minutes ago, Carnis said:

So.. I'd like to see this build with 21 thermoregulators, without breaking hydrogen pipes.

They don't have to be in series.  I would have 21 different hydrogen loops.  Well, probably not 21.  Probably more like 10.

[SkunkMaster]

3 hours ago, Zarquan said:

OK.  Take 2 on the math. 

Starting with 10 kg sour gas 538.9 C, which results in 6.7 kg natural gas -161.5 C, 5.025 kg polluted water -20 C, 1.675 kg of CO2 -20 C, and 10 kg 70 C crude oil. 

I transfer heat from sour gas to crude oil up to 400 C.  That cools the sour gas from 538.9 to 245 C.

I then transfer heat from sour gas to natural gas, cooling it to 121.7 C.  This heats the natural gas by 159.4 C, from -0.5 C to 158.9 C.

I then transfer heat from sour gas to polluted water.  I cool the sour gas to -0.5 C, which heats the polluted water to 90 C.

I then transfer all the heat I can from the -0.5 C sour gas to the -161.5 C natural gas.  I heat the natural gas to x, cooling the sour gas to -125 C, heating the natural gas to -0.5 C. 

That leaves 36.5 C that needs to be removed, resulting in 692,350 J that need to be removed.  We will use thermoregulators to move the heat from the sour gas to the polluted water and CO2, heating each to 110 C.  The polluted water can take 421,800 J.  The CO2 can take 184,200 J of heat.  That covers 606,000 J of heat, therefore only leaving 86,300 to be removed.  That can be dealt with by using 7.2 wheezeworts. 

It will take 21 thermoregulators to manage this heat transfer at the rate of 10 kg/s of sour gas.

21 thermoregulators costs 5040 W to run.  Easily covered by the power gains.

Once we can move the sulfur, we can reduce this cost significantly and the system should net cool.

You could use a thermal pump to raise the temp of the natural gas to around 170c.

[Carnis]

So I thought of it one more time.

I already have a steady source of 124C sour gas at up to 10kg/s.

If I build a counter flow heat exchanger connected by diamond tempshift & (radiant oilpipe near the low delta-T zone) one side sourgas, otherside natural gas and pump The ng out at 124C, I get the following equation:

10 000g x 1.898 J/g/K x 285K (from +124 to -161) = 5 409 300 J

Now the NG coolant is assumed at 100% efficiency:

6667g x 2,191 J/g/K x 285K = 4 163 100J

This means I need 1 246 000/second net cooling.

Now I introduce 10kg/s counterflow polluted water to the hot side at water SHC 4,179. How much does my process heat up the water? At 100% efficiency 1 246 000/4,179/10000 = 29,8K..

So If I position the waterpipes properly, and Make an efficient heat exchanger to the bottom NG side methane boils cooling the sour side, I can condense all the sourgas with a single AETN.

Edit:

At 10kg/sec AETN makes delta-T of 4K/s to sourgas, so 1 methane aquatuner is necessary...

[Carnis]

So I made a debug test using 25C pWater, methane aquatuner, AETN, cool natural gas, liquid pump.

pWater basically resets The heat of The sourgas to its temperature. So slush geyser or pW aquatuner is a good starting point For -20C sour.

Methane aquatuner is too unstable, pipes break whenever you add new sourgas.

AETN heat deletion is negligible, almost overpowered by liquid pump 10w.

*

The crude-sour-ng machine will Be Hell to build.

But hydrogen loop with stacks of thermoregs can work.