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Does phase change delete heat?


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In some previous discussions on this forum someone somewhere mentioned that phase change costs energy. 

Can someone tell me how this works?

If all phase changes indeed consume energy I would like to explore the options of cooling my base using that mechanic. I'm thinking about an aquatuner and some automation contineously vaporizing and condensing clean water.

Does someone know more about the phase change mechanics? Or do they only apply because of different heat capacities?

Testing using the debug painter, it looks like both clean and polluted water lose 1.5 degrees when they evaporate. Polluted water crosses the 122.4C threshold to become 120.9 C steam and dirt, while clean water crosses the 102.4 C threshold to become 100.9 C steam.

Interestingly, steam also loses 1.5 degrees going the other direction: crossing the 96.3 C threshold yields 94.8 C water.

So, in theory, you could make a cooling system as you describe. 

At least with crude turning in to petroleum the temperatures were close enough to the same that if it was changing it wasn't enough to really matter.

I may have been interpreting it wrong as well.  The walls were over 400 degrees and the crude was 396 and transitioning so possibly there was heat transferring in to the crude that put it over 400 for a moment and then it boiled out down to what looked like a steady slowly increasing 396  That could mean it was about 1% heat loss on transition?

I debug mode painted in 700c(973.15k) petrol in to an abyssalite surrounded vacuum and it turned in to 697.5c natural gas.

697.5c is 970.65k so there is a change

They both have different heat capacity so I would bet if you mathed it around the petrol transition you would get some more useful values.

 

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