PhailRaptor Posted April 9, 2018 Share Posted April 9, 2018 Trying to really wrap my brain around the math on Geyser output. It's somewhat annoying simply because of how the data is displayed in the tooltip. I get that Eruption Period is how long/often the Geyser is actually producing. A "good" Geyser will have a higher percentage between the listed values. For example, a Geyser that is listed as "371 seconds out of 490 seconds" is a pretty fantastic find, because that's like 75% uptime, right? During that time, the actual production rate of the Geyser is applied, right? "Good" Geysers would vary based on what kind it is, but with clean Water for example, you'd be looking for something > 5 kg/s, yes? But where does the Active Period fit in? I've yet to get a food supply able to sustain a Tenured Scientist, let alone have the chance to send them in to analyze the Geyser. I'm assuming this is related to the fact that, visually, Geysers do not emit substance 100% of the time? So to get the "true" output of your Geyser on each of it's state rotations, you'd have to determine what portion of it's Eruption Period it is actually Active, then take that duration and multiply by the production rate? Link to comment https://forums.kleientertainment.com/forums/topic/89656-whats-the-geyser-output-formula/ Share on other sites More sharing options...
Grimgaw Posted April 9, 2018 Share Posted April 9, 2018 In my example it's 7.2 * (73/226) * (79.1/168.3) = 1.1 kg/s 29 minutes ago, PhailRaptor said: I've yet to get a food supply able to sustain a Tenured Scientist, let alone have the chance to send them in to analyze the Geyser. Berry Sludge is my go to here. I'm farming Bristles and 'foraging' for sleet. Frankly with the amount of wheat on map I won't have to farm it for a loooong time. Link to comment https://forums.kleientertainment.com/forums/topic/89656-whats-the-geyser-output-formula/#findComment-1024710 Share on other sites More sharing options...
PhailRaptor Posted April 9, 2018 Author Share Posted April 9, 2018 8 minutes ago, Grimgaw said: In my example it's 7.2 * (73/226) * (79.1/168.3) = 1.1 kg/s So for "true" output, you multiply both of the %s for Eruption and Active Period by the output rate? Seems I was looking at Eruption and Active Period backwards, as well. Active Period is the overall rotation, and Eruption is when it actually produces. Link to comment https://forums.kleientertainment.com/forums/topic/89656-whats-the-geyser-output-formula/#findComment-1024712 Share on other sites More sharing options...
Grimgaw Posted April 9, 2018 Share Posted April 9, 2018 1 minute ago, PhailRaptor said: So for "true" output, you multiply both of the %s for Eruption and Active Period by the output rate? That's right. Link to comment https://forums.kleientertainment.com/forums/topic/89656-whats-the-geyser-output-formula/#findComment-1024713 Share on other sites More sharing options...
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